Opened 18 years ago
Closed 17 years ago
#4088 closed (fixed)
Not able to filter() on foreign keys.
Reported by: | Owned by: | nobody | |
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Component: | Database layer (models, ORM) | Version: | dev |
Severity: | Keywords: | filter foreignkey, qs-rf-fixed | |
Cc: | Triage Stage: | Accepted | |
Has patch: | yes | Needs documentation: | no |
Needs tests: | yes | Patch needs improvement: | no |
Easy pickings: | no | UI/UX: | no |
Description
I'm trying to filter by a value that is contained in a foreign key. I've seen this done in the django documentation (the blog example).
Here are my models:
class Students(models.Model): ssn = models.CharField(unique=True, maxlength=11) name = models.CharField(blank=True, maxlength=50) address = models.CharField(blank=True, maxlength=50) dob = models.DateField(null=True, blank=True) email = models.CharField(blank=True, maxlength=50) level = models.CharField(blank=True, maxlength=5) def __str__(self): return self.ssn class Takes(models.Model): student = models.ForeignKey(Students, to_field='ssn', db_index=True, db_column='ssn') course = models.ForeignKey(Courses, to_field='cid', db_index=True, db_column='cid') semester = models.ForeignKey(Semesters, to_field='sname', db_index=True, db_column='sname') grade = models.CharField(blank=True, maxlength=2) def __str__(self): return "%s - %s" % (self.course.cid, self.semester.sname)
The other models aren't relevant to the question. We are just focusing on the student foreign key inside Takes.
Now, here is an example of me trying to filter by someone's name
>>> Takes.objects.filter(student__name="Kevin Smith") [] >>> Takes.objects.get(id=1).student.name 'Kevin Smith' >>>
I've also tried every combination of icontains. To circumvent this, I've been using the code below (if it helps)
takes = Takes.objects.all() takes2 = [] for x in takes: if (x.student.name).lower().find("kev".lower()) != -1: takes2.append(x)
And takes2[0].student.name returns "Kevin Smith".
Maybe I'm missing something totally, which I would love to know. But this feels like a bug to me.
Attachments (1)
Change History (11)
follow-up: 2 comment:1 by , 18 years ago
Triage Stage: | Unreviewed → Accepted |
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comment:2 by , 18 years ago
That's a great idea that I didn't think of. This is what I get from the mysql log:
SELECT Takes
.id
,Takes
.ssn
,Takes
.cid
,Takes
.sname
,Takes
.grade
FROM Takes
INNER JOIN Students
AS Takes__student
ON Takes
.ssn
= Takes__student
.id
WHERE (Takes__student
.name
= 'Kevin Smith')
The problem I see here is the Takes.ssn = Takesstudent.id
It's trying to compare the social security number to the auto incrementing primary key id.
If I open mysql and type in the same query but change that to Takes.ssn = Takesstudent.ssn it works how I want it to.
So is there something I need to make clear in my models so this works correctly?
comment:3 by , 18 years ago
Erm, should have used code blocks.
Here is what Takes.objects.filter(student__name="Kevin Smith")
generates:
SELECT `Takes`.`id`,`Takes`.`ssn`,`Takes`.`cid`,`Takes`.`sname`,`Takes`.`grade` FROM `Takes` INNER JOIN `Students` AS `Takes__student` ON `Takes`.`ssn` = `Takes__student`.`id` WHERE (`Takes__student`.`name` = 'Kevin Smith')
And this is what I want:
SELECT `Takes`.`id`,`Takes`.`ssn`,`Takes`.`cid`,`Takes`.`sname`,`Takes`.`grade` FROM `Takes` INNER JOIN `Students` AS `Takes__student` ON `Takes`.`ssn` = `Takes__student`.`ssn` WHERE (`Takes__student`.`name` = 'Kevin Smith')
Just change that id near the end to ssn.
comment:4 by , 18 years ago
I'm too busy to make a patch, but perhaps you're able to help yourself with a few hints.
The bug is in django/db/models.query.py, function lookup_inner, in this portion:
# Does the name belong to a one-to-one, many-to-one, or regular field? field = find_field(name, current_opts.fields, False) if field: if field.rel: # One-to-One/Many-to-one field new_table = current_table + '__' + name new_opts = field.rel.to._meta --> new_column = new_opts.pk.column join_column = field.column raise FieldFound elif path: # For regular fields, if there are still items on the path, # an error has been made. We munge "name" so that the error # properly identifies the cause of the problem. name += LOOKUP_SEPARATOR + path[0] else: raise FieldFound
The statement new_column = new_opts.pk.column
always chooses the primary key as join target, it should use the right value of field.rel
or field.rel.to
, no idea. If you play with it a bit in an ipython shell, you'll see what you need to put there.
comment:5 by , 18 years ago
Last comment was me. Sorry, but I set my browser to session only cookies ...
by , 18 years ago
Attachment: | newcolumn.diff added |
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comment:6 by , 18 years ago
Has patch: | set |
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Needs tests: | set |
Version: | 0.96 → SVN |
I found the problem and I attached a patch to fix it. Basically it uses the field you specify in the ForeignKey
using to_field="whatever". Which seems to be the correct way of doing it. If you don't specify this field, django
automatically sets it to the primary key of the model you're relating to, so it works either way.
comment:7 by , 17 years ago
I tested the patch and it fixed my issues mostly for bug #4306, though there is still one case that it does not fix.
http://code.djangoproject.com/ticket/4306#comment:2
comment:8 by , 17 years ago
Keywords: | qs-rf-fixed added |
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comment:10 by , 17 years ago
Resolution: | → fixed |
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Status: | new → closed |
(In [7477]) Merged the queryset-refactor branch into trunk.
This is a big internal change, but mostly backwards compatible with existing
code. Also adds a couple of new features.
Fixed #245, #1050, #1656, #1801, #2076, #2091, #2150, #2253, #2306, #2400, #2430, #2482, #2496, #2676, #2737, #2874, #2902, #2939, #3037, #3141, #3288, #3440, #3592, #3739, #4088, #4260, #4289, #4306, #4358, #4464, #4510, #4858, #5012, #5020, #5261, #5295, #5321, #5324, #5325, #5555, #5707, #5796, #5817, #5987, #6018, #6074, #6088, #6154, #6177, #6180, #6203, #6658
I wonder if the
to_field
anddb_column
are messing things up. Can you tell if the SQL being generated by theTakes.objects.filter(student__name="Kevin Smith")
is correct?