Opened 9 years ago

Closed 9 years ago

#18463 closed Bug (fixed)

Using len() in Paginator object can raise an error

Reported by: renato@… Owned by: Claude Paroz
Component: Core (Other) Version: master
Severity: Normal Keywords:
Cc: Triage Stage: Accepted
Has patch: no Needs documentation: no
Needs tests: no Patch needs improvement: no
Easy pickings: no UI/UX: no

Description (last modified by Claude Paroz)

I'm getting the following error if I try to run a piece of code through my

Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "/home/mp/webapps/django/rep/app/", line 331, in search_species
    print len(recs)
  File "/home/mp/webapps/django/lib/python2.7/django/core/", line 88, in __len__
    return len(self.object_list)
  File "/home/mp/webapps/django/lib/python2.7/django/db/models/", line 87, in __len__
    self._result_cache = list(self.iterator())
  File "/home/mp/webapps/django/lib/python2.7/django/db/models/", line 284, in iterator
    model_cls = deferred_class_factory(self.model, skip)
  File "/home/mp/webapps/django/lib/python2.7/django/db/models/", line 180, in deferred_class_factory
    return type(name, (model,), overrides)
TypeError: type() argument 1 must be string, not unicode

Strangely, if I run a similar code directly in the Django shell, everything goes well. The code looks like this:

from app.models import MyClass
qs = MyClass.objects.all()
from django.core.paginator import Paginator
paginator = Paginator(qs, 25)
recs =
print len(recs)

So you have to run this code through a method in to get a crash in the last line.

I'm afraid I have no idea of what's going on and how to properly fix this, but if I change the offending line from the traceback by forcing str() in the name parameter it works:

return type(str(name), (model,), overrides)

Change History (2)

comment:1 Changed 9 years ago by Claude Paroz

Description: modified (diff)
Owner: changed from nobody to Claude Paroz
Status: newassigned
Triage Stage: UnreviewedAccepted

This bug is only triggered when the model name in deferred_class_factory is truncated (> 80 chars) and then a Unicode string is returned. Calling str() seems a good solution.

comment:2 Changed 9 years ago by Claude Paroz <claude@…>

Resolution: fixed
Status: assignedclosed

In [3dd5d726d1c3bf8f5901c992d7586e5ec146bc2d]:

Fixed #18463 -- Forced type() argument to be a byte string

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