Opened 17 years ago
Closed 17 years ago
#5514 closed (wontfix)
Consistency issue when using ForeignKeys
Reported by: | Philippe Raoult | Owned by: | Philippe Raoult |
---|---|---|---|
Component: | Core (Other) | Version: | dev |
Severity: | Keywords: | select_related | |
Cc: | Triage Stage: | Design decision needed | |
Has patch: | no | Needs documentation: | no |
Needs tests: | no | Patch needs improvement: | no |
Easy pickings: | no | UI/UX: | no |
Description
Consider the following models:
class Operand(models.Model): value_1 = models.CharField(maxlength=200) value_2 = models.CharField(maxlength=200) class Operation(models.Model): arg = models.ForeignKey(Operand)
Now let's suppose we want to do some work on Operands:
>>> common_arg = Operand(value_1="val1", value_2="val2") >>> common_arg.save() >>> op1 = Operation(arg = common_arg) >>> op2 = Operation(arg = common_arg) >>> op1.save() >>> op2.save() >>> operations = Operation.objects.all().select_related() >>> operations [<Operation: Operation object>, <Operation: Operation object>] >>> operations[0].arg.value_1 = "new_val1" >>> operations[0].arg.save() >>> operations[1].arg.value_2 = "new_val2" >>> operations[1].arg.save() >>> modified_arg = Operand.objects.get(id=1) # OOPS we lost one change here !! >>> modified_arg.value_1 u'val1' >>> modified_arg.value_2 u'new_val2' # restore the initial state >>> modified_arg.value_2 = "val2" >>> modified_arg.save() # this is not limited to select_related but pervasive with FKs >>> work_to_do = [(op, op.arg) for op in Operation.objects.all()] >>> work_to_do[0][1].value_1 = "new_val1" >>> work_to_do[0][1].value_1 'new_val1' # oops, operation 2 will use the outdated argument >>> work_to_do[1][1].value_1 u'val1'
#17 could provide a solution for this issue: caching instances in memory so get() and friends can return the instance we already have instead of creating a new, distinct one.
The issue is especially easy to encounter with select_related because all related fields will be preloaded in distinct instances in memory. Walking Operation.objects.all() and
modifying the Operands from there would load an new instance from the DB for each operation and work as expected in most cases.
Change History (2)
comment:1 by , 17 years ago
Status: | new → assigned |
---|---|
Triage Stage: | Unreviewed → Design decision needed |
comment:2 by , 17 years ago
Resolution: | → wontfix |
---|---|
Status: | assigned → closed |
Though I agree this is counter-intuitive, this isn't going to be fixed. Doing so would require a complex identity-mapper style solution, and that doesn't fit with Django's "80% ORM" philosophy.