#29976 closed Uncategorized (invalid)
How to perform Group by on Union of two models
| Reported by: | Sandeep | Owned by: | nobody |
|---|---|---|---|
| Component: | Database layer (models, ORM) | Version: | 2.1 |
| Severity: | Normal | Keywords: | Union and annotate(Count('')) |
| Cc: | k.sandeep44@… | Triage Stage: | Unreviewed |
| Has patch: | no | Needs documentation: | no |
| Needs tests: | no | Patch needs improvement: | no |
| Easy pickings: | no | UI/UX: | no |
Description (last modified by )
I have two models like this:
class Story(models.Model):
name = models.TextField(db_column='NAME') # Field name made lowercase.
status = models.TextField(db_column='STATUS') # Field name made lowercase.
class Bug(models.Model):
name = models.TextField(db_column='NAME') # Field name made lowercase.
status = models.TextField(db_column='STATUS') # Field name made lowercase.
I would like to get count of Unique status from above two tables
Query: Select new_table.status, Count(new_table.name) from (select status, name from Story Union select status, name from Bug) new_table group by new_table.status
Change History (3)
comment:1 by , 7 years ago
| Severity: | Release blocker → Normal |
|---|
comment:2 by , 7 years ago
| Resolution: | → invalid |
|---|---|
| Status: | new → closed |
comment:3 by , 7 years ago
| Description: | modified (diff) |
|---|
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The Release Blocker status is for data loss bugs and regressions from previous versions of Django. As far as I can see this isn't that.
There's no bug report here. Please see TicketClosingReasons/UseSupportChannels for help.