Print original exception when an unknown error occurs in template
|Reported by:||Owned by:||Adrian Holovaty|
|Has patch:||no||Needs documentation:||no|
|Needs tests:||no||Patch needs improvement:||no|
We had a problem when we updated a Model, but not the DB. Loading the template failed and we got a useless error message because of catching the original exception and wrapping it. Only the TemplateSyntaxError was printed, not the original exception which was very misleading. This was with 0.91, but HEAD has the same issue. Below is a patch that fixes the problem. I didn't see a way to upload a file as a patch.
--- template/init.py.orig 2006-05-12 11:14:27.000000000 -0700
+++ template/init.py 2006-05-12 11:14:00.000000000 -0700
@@ -90,7 +90,20 @@
builtins = 
+ def str(self):
+ import cStringIO as StringIO
+ except ImportError:
+ import StringIO
+ output = StringIO.StringIO()
+ # Check if we wrapped an exception and print that too.
+ if hasattr(self, 'exc_info'):
+ import traceback
+ output.write('\n\nOriginal ')
+ e = self.exc_info
+ traceback.print_exception(e, e, e, 500, output)
+ return output.getvalue()
"pop() has been called more times than push()"