#16693 closed Bug (invalid)
Unregistering ModelAdmin view and registering it again changing its contents is not realized when invoking it.
Reported by: | heidar_rafn | Owned by: | nobody |
---|---|---|---|
Component: | contrib.admin | Version: | 1.3 |
Severity: | Normal | Keywords: | |
Cc: | Triage Stage: | Unreviewed | |
Has patch: | no | Needs documentation: | no |
Needs tests: | no | Patch needs improvement: | no |
Easy pickings: | no | UI/UX: | no |
Description
When trying to make a change to the list_per_page option of a ModelAdmin class instance,
it seems that the change is not activated on the fly.
I first "unregister" the old ModelAdmin class and then "register" a new one (which is actually created)
but when trying to invoke the view, the old one is used, it looks like it is cached somewhere and the url-mechanism
is not using the re-created view, but invokes the old one.
After some investigation, I managed to create a work around that demonstrates what might be a bug,
see the code snippets, especially the "changelist_view" function - if it is omitted,
the behavior I am describing happens.
Here are code snippets that demonstrate this:
# settings.py ... FLIGHTADMININSTANCE = None ...
# myapp/admin.py ... from django.conf import settings from myapp.models import ConfigParameters ... class FlightAdmin(admin.ModelAdmin): try: list_per_page = int(ConfigParameters.objects.get(name="FLIGHTADMIN_LIST_PER_PAGE").value) except: list_per_page = 5; ... def __init__(self, *args, **kwargs): super(FlightAdmin, self).__init__(*args, **kwargs) # store globally the object instance pointer settings.FLIGHTADMININSTANCE = self # following debug shows that the list_per_page is really changed print "FlightAdmin created", self, self.list_per_page def changelist_view(self, request, extra_context=None, **kwargs): # NOTE: following is to override some probably cached instance of the view # and enables the changed view to be used instead of the first instance created # of the FlightAdmin class if this hook is not used return super(FlightAdmin, settings.FLIGHTADMININSTANCE).changelist_view(request, extra_context=extra_context) ... admin.site.register(Flight, FlightAdmin) ... def list_per_page_change(sender, instance, created, **kwargs): if instance.name == 'FLIGHTADMIN_LIST_PER_PAGE': # yes - the value is changing, change the FlightAdmin class accordingly admin.site.unregister(Flight) try: admin.site.register(Flight, FlightAdmin, list_per_page=int(instance.value)) except: admin.site.register(Flight, FlightAdmin) post_save.connect (list_per_page_change, sender=ConfigParameters)
Change History (2)
comment:1 by , 13 years ago
Resolution: | → invalid |
---|---|
Status: | new → closed |
comment:2 by , 13 years ago
Thanks for the comments. My problem to solve was to allow the user to configure the
ModelAdmin.list_per_page
option, but I obviously did not describe it well enough and I did not read the documentation thoroughly enough in order to find the easy solution.
This problem is actually very easy to solve with the documented "ModelAdmin.changelist_view(self, request, extra_context=None)" option like this:
def changelist_view(self, request, extra_context=None, **kwargs): try: self.list_per_page = int(ConfigParameters.objects.get(name="FLIGHTADMIN_LIST_PER_PAGE").value) except: self.list_per_page = 5; return super(FlightAdmin, self).changelist_view(request, extra_context=extra_context)
You shouldn't modify settings at runtime — never. The docs couldn't be more clear: https://docs.djangoproject.com/en/dev/topics/settings/#altering-settings-at-runtime
Even if your code worked, the settings would only be updated in the current process. On a multiprocess webserver (anything but the built-in dev server) you will have different settings in each process, and you will obtain random results, depending on which process handles your request. On a threaded webserver, you would get race conditions between
settings.FLIGHTADMININSTANCE = self
andsuper(FlightAdmin, settings.FLIGHTADMININSTANCE)
, which is likely to break in horrible ways.Finally,
unregister
is undocumented; there's no commitment on what it does.To sum up, I'm sorry, but your code has such fundamental problems that I can't figure out if there's really a problem in Django. If you can demonstrate that Django doesn't behave according to its documentation or reasonable expectations, please reopen the ticket.