|Version 27 (modified by 11 years ago) (diff),|
The previous version of this page is obsolete due to the model syntax change. Additionally, there's now a better reference for this topic:
magic-removal: Model Inheritance
This is a proposal for how subclassing should work in Django. There a lot of details to get right, so this proposal should be very specific and detailed. Most of the ideas here come from the thread linked below:
Here are some additional notes from Robert Wittams on allowing different storage models.
For subclassing, there are 3 main issues:
- How do we model the relations in SQL?
- How do joins work?
- How does the API work?
Note that I have only provided examples for single inheritance here. Is multiple inheritance worth supporting?
The examples will use the following models:
class Place(models.Model): name = models.CharField(maxlength=50) class Restaurant(Place): description = models.TextField() class ItalianRestaurant(Restaurant): has_decent_gnocchi = models.BooleanField()
1. Modeling parent relations in SQL?
The general consesus seems to be this:
CREATE TABLE "myapp_place" ( "id" integer NOT NULL PRIMARY KEY, "name" varchar(50) NOT NULL ); CREATE TABLE "myapp_restaurant" ( /* PRIMARY KEY REFERENCES "myapp_places" ("id") works for postgres, what about others? */ /* This works in MySQL too. -- Andy Dustman */ "id" integer NOT NULL PRIMARY KEY REFERENCES "myapp_places" ("id"), "description" text NOT NULL ); CREATE TABLE "myapp_italianrestaurant" ( "id" integer NOT NULL PRIMARY KEY REFERENCES "myapp_restaurant" ("id"), "has_decent_gnocchi" bool NOT NULL );
2. Modeling joins in SQL
When we want a list of
ItalianRestaurants, we obviously need all the fields from myapp_restaurant and myapp_place as well. This could be accomplished by inner joins. It would look something like this:
SELECT ... FROM myapp_italianrestaurant as ir INNER JOIN myapp_restaurant as r ON ir.restaurant_id=r.id INNER JOIN myapp_place as p ON r.place_id=p.id
But what if we want a list of
Places, what should we do? We can either just get the places:
SELECT ... FROM myapp_place
Or we can get everything with left joins (this allows the iterator to return objects of the appropriate type, rather than just a bunch of
SELECT ... FROM myapp_place as p LEFT JOIN myapp_restaurant as r ON r.place_id=p.id LEFT JOIN myapp_italianrestaurant as ir ON ir.restaurant_id=r.id
Imagine we have more than one subclass of
Place though. The join clause and the column list would get pretty hefty. This could obviously get unmanageable pretty quickly.
I think some dbs have a maximum number of joins (something like 16), and even within the maximum, the query optimizer will either spend a while deciding which way to best join the tables or it will give up and choose the wrong way quickly. This wording is FUD-- I'll try to find specifics. --jdunck
MySQL-4.1 and newer can handle up to 61 tables in a JOIN or VIEW (5.0 and newer). Unclear what the limit is for 4.0 and older. -- Andy Dustman
There must be major performance problems with performing that many joins in a query. What's wrong with making the default behaviour to grab only the base fields, and documenting that? (except for the fact that subclass-specific methods might break .. hm.) --harmless
Another possibility is to create VIEWs:
CREATE TABLE "myapp_place" ( "id" integer NOT NULL PRIMARY KEY, "name" varchar(50) NOT NULL ); CREATE TABLE "myapp_restaurant_base" ( "id" integer NOT NULL PRIMARY KEY REFERENCES "myapp_places" ("id"), "description" text NOT NULL ); CREATE VIEW "myapp_restaurant" AS SELECT a."id", a."name", b."description" FROM "myapp_place" AS a LEFT JOIN "myapp_restaurant_base" AS b ON a."id"=b."id" ; CREATE TABLE "myapp_italianrestaurant_base" ( "id" integer NOT NULL PRIMARY KEY REFERENCES "myapp_restaurant" ("id"), "has_decent_gnocchi" bool NOT NULL ); CREATE VIEW "myapp_italianrestaurant" AS SELECT a."id", a."name", b."description", c."has_decent_gnocchi" FROM "myapp_place" AS a LEFT JOIN "myapp_restaurant_base" AS b ON a."id"=b."id" LEFT JOIN "myapp_italianrestaurant_base" AS c on a."id"=c."id" ;
In MySQL-5.0, most of the theoretically-updatable VIEWs are updatable, but currently, "You cannot use UPDATE to update more than one underlying table of a view that is defined as a join." so unfortunately this doesn't work (yet):
mysql> INSERT INTO "myapp_italianrestaurant" ("name","description","has_decent_gnocchi") -> VALUES ('DePalma\'s', 'Fine Italian Dining', 1); ERROR 1288 (HY000): The target table myapp_italianrestaurant of the INSERT is not updatable
However, it is possible to do this:
mysql> INSERT INTO "myapp_place" ("id","name") VALUES (1,'DePalma\'s'); Query OK, 1 row affected (0.00 sec) mysql> INSERT INTO "myapp_restaurant_base" ("id","description") VALUES (1,'Fine Italian Dining'); Query OK, 1 row affected (0.01 sec) mysql> INSERT INTO "myapp_italianrestaurant_base" ("id","has_decent_gnocchi") VALUES (1,1); Query OK, 1 row affected (0.00 sec) mysql> UPDATE "myapp_italianrestaurant" SET "description"='Exquisite Italian Dining'; Query OK, 1 row affected (0.00 sec) Rows matched: 1 Changed: 1 Warnings: 0 mysql> SELECT * FROM myapp_italianrestaurant; +----+-----------+--------------------------+--------------------+ | id | name | description | has_decent_gnocchi | +----+-----------+--------------------------+--------------------+ | 1 | DePalma's | Exquisite Italian Dining | 1 | +----+-----------+--------------------------+--------------------+ 1 rows in set (0.03 sec)
Unfortunately if you try to update name and description at the same time, this fails. The VIEW scheme would still be useful for SELECT, but I think the base tables will have to be updated directly. At least VIEWs buy you an easier SELECT statement without JOINs. It's possible to handle some of the VIEW updating with INSTEAD OF triggers with Oracle, IBM DB2, and MS SQL (PostgreSQL uses CREATE RULE ... AS ON (INSERT|UPDATE) ... DO INSTEAD), but that kind is not in MySQL yet. I'm not sure how much effort it's worth. -- Andy Dustman
Another option is to lazily load objects like
ItalianRestaurant while we're iterating over
Place.objects.all(), but that requires a lot of database queries. Either way, doing this will be expensive, and api should reflect that. You're much better off just using
Places fields if you are going to iterate over
The following API examples assume we have created these objects:
p = Place(name='My House') r = Restaurant(name='Road Kill Cafe', description='Yuck!') ir = ItalianRestaurant(name="Ristorante Miron", description="Italian's best mushrooms restaurant", has_decent_gnocchi=True)
For the following examples, assume
|D.|| || 'Yuck!' or |
Change the current usage of subclassing
class MyArticle(Article): ...fields... class META: module_name = 'my_articles' remove_fields = ...some fields...
would change to:
class MyArticle(meta.Model): ...fields... class META: copy_from = Article remove_fields = ...some fields...
Ramblings on Magic Removal Subclassing from the Pycon Sprint
Consider the following variation on the above restaurant example:
class Place(models.Model): name = models.CharField(maxlength=50) foo = 1 def bar(self): return 2
If Restaurant were to inherit from this, it would not automatically have a 'name' CharField. This is because Django uses a metaclass to modify the default class creation behavior. The ModelBase metaclass creates a new class from scratch, and then selectively pulls items from the Place class as defined above and adds them to this new class, which allows it to handle Field objects specially. For each of the class's attributes, add_to_class() is called. If add_to_class finds a 'contribute_to_class' attribute, ModelBase knows it is dealing with a Field object, and calls contribute_to_class. Otherwise, it just adds it to the new class via setattr(). Thus, by the time the Restaurant class is created, the Place class which it inherits from actually looks more like this:
class Place(models.Model): _meta = ... foo = 1 def bar(self): return 2
Thus, there is simply no 'name' field for it to inherit. So, we need to have ModelBase walk through the parent classes and call contribute_to_class on each of the fields found in _meta.fields. As we walk the inheritance tree, we look for a '_meta' attribute to determine if our current node is a Model. Otherwise, it is either a mixin class or the Model class iteself.
We can keep track of the parent hierarchy by creating _meta.parents, and having each ancestor of Model add to it in a recursive fasion, by adding the following to ModelBase.new():
# Build complete list of parents for base in bases: if '_meta' in dir(base): new_class._meta.parents.append(base) new_class._meta.parents.extend(base._meta.parents)
We can then add all of the parent fields to the new class like so:
# Add Fields inherited from parents for parent in new_class._meta.parents: for field in parent._meta.fields: field.contribute_to_class(new_class, field.name)
That should pretty much be it for the object side of things; what's left is the database side of things (ie, the hard part).