Opened 5 years ago
Last modified 4 years ago
#32559 closed New feature
Add attribute 'step' to FloatField. — at Version 11
| Reported by: | Jacob Rief | Owned by: | Kapil Bansal |
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| Component: | Forms | Version: | dev |
| Severity: | Normal | Keywords: | FloatField, NumberInput, step |
| Cc: | Triage Stage: | Ready for checkin | |
| Has patch: | yes | Needs documentation: | no |
| Needs tests: | no | Patch needs improvement: | no |
| Easy pickings: | no | UI/UX: | no |
Description (last modified by )
I reviewed that pull request and after some testing I came to the conclusion, that math.isclose with a tolerance of 1e-9 is the best solution to fix the floating point rounding errors. All other approaches did not work properly or were far too complicated.
Change History (11)
comment:1 by , 5 years ago
| Triage Stage: | Unreviewed → Accepted |
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comment:3 by , 5 years ago
| Owner: | changed from to |
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| Status: | new → assigned |
comment:4 by , 5 years ago
| Description: | modified (diff) |
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| Has patch: | set |
comment:5 by , 5 years ago
| Summary: | Add attribute 'step' to FloatField and DecimalField → Add attribute 'step' to FloatField. |
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comment:6 by , 5 years ago
| Description: | modified (diff) |
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comment:7 by , 5 years ago
| Needs tests: | set |
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comment:8 by , 5 years ago
| Description: | modified (diff) |
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| Needs tests: | unset |
comment:9 by , 5 years ago
On the forum, Kapil wrote:
Hi,
I was working on ticket 32559 to add step in FloatField but how to write validation check for this.
Due to python floating point issues, I am not able to validate whether field value is of given step_size or not
The loss of precision in floating points is a real issue. The normal way to validate would be to use the modulo operator to check there is no remainder after dividing by the step, but this isn't possible in floating points with common decimal steps like 0.1:
>>> step = 0.1 >>> 1 % step == 0 False >>> 1 % step 0.09999999999999995
This problem cannot be solved for FloatField - I suggest we move the ticket to modify DecimalField, as Decimal objects do not have the same problem:
>>> from decimal import Decimal
>>> step = Decimal('0.1')
>>> Decimal(1) % step == 0
True
>>> Decimal(1) % step
Decimal('0.0')
We'd want to enforce that step is given as a Decimal.
The float problem can also occur when constructing a Decimal from a float:
>>> Decimal(0.1)
Decimal('0.1000000000000000055511151231257827021181583404541015625')
Perhaps we should have a check that the given step does not have more than 10 digits after the decimal point?
comment:10 by , 5 years ago
Hi,
I got a reply on mailing list to use math.isclose function. Pull Request is already opened to be reviewed
comment:11 by , 5 years ago
| Description: | modified (diff) |
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Thank you. Sounds like a perfectly valid use case.