QuerySet.update() fails on MySQL if a subquery references the base table

[Paulo]

Given the models below:

class House(models.Model):
    name = models.CharField(max_length=200)

class Room(models.Model):
    name = models.CharField(max_length=200)
    house = models.ForeignKey(House, on_delete=models.CASCADE)

The following query fails:

houses_with_suites = House.objects.filter(room__name__icontains='suite')
Room.objects.filter(house__in=houses_with_suites).update(name='suite')

With this error:

OperationalError: (1093, "You can't specify target table 'mysql_test_room' for update in FROM clause")

I think this has been around for a while (#20300).

I've confirmed this only happens in MySQL. It works on PostgresSQL and SQLite.

[Sonu kumar]

This doesn't look to be a bug in Django. This is a more of MySQL query parser bug.

Query generated by Django ORM

UPDATE `CoreApp_room` SET `name` = 'suite' 
WHERE `CoreApp_room`.`house_id` IN 
( SELECT U0.`id` FROM `CoreApp_house` U0 
   INNER JOIN `CoreApp_room` U1 
  ON (U0.`id` = U1.`house_id`) 
  WHERE U1.`name` LIKE '%suite%'
)

As we can the query generated by Django is totally valid but MySQL server has raise error

[Oskar Persson]

Replying to Sonu kumar:

This doesn't look to be a bug in Django. This is a more of MySQL query parser bug.

This is not a query parser bug but a documented limitation of ​MySQL:

You can use a subquery for assignment within an UPDATE statement because subqueries are legal in UPDATE and DELETE statements as well as in SELECT statements. However, you cannot use the same table (in this case, table t1) for both the subquery FROM clause and the update target.

and ​MariaDB:

It's not possible to both modify and select from the same table in a subquery. For example:

DELETE FROM staff WHERE name = (SELECT name FROM staff WHERE age=61);
ERROR 1093 (HY000): Table 'staff' is specified twice, both 
  as a target for 'DELETE' and as a separate source for data