Opened 9 years ago
Last modified 9 years ago
#25813 closed Bug
models.py by 'inspectdb' command gives me error — at Initial Version
Reported by: | Minsoo Kim | Owned by: | nobody |
---|---|---|---|
Component: | Database layer (models, ORM) | Version: | 1.8 |
Severity: | Normal | Keywords: | inspectdb, MySQL |
Cc: | Triage Stage: | Unreviewed | |
Has patch: | no | Needs documentation: | no |
Needs tests: | no | Patch needs improvement: | no |
Easy pickings: | no | UI/UX: | no |
Description
Hi, I'm currently using Django with MySQL and having some trouble with models.py generated by inspectdb command.
So, DDL First :
CREATE TABLE YDB_Collects ( COriginal_Data_Type_ID VARCHAR(16) NOT NULL, CTask_Name VARCHAR(16) NOT NULL, PRIMARY KEY (COriginal_Data_Type_ID, CTask_Name), INDEX FK_COLLECTS_TASK (CTask_Name), CONSTRAINT FK_COLLECTS_ORIGINAL_DATA_TYPE FOREIGN KEY (COriginal_Data_Type_ID) REFERENCES YDB_Original_Data_Type (Original_Data_Type_ID), CONSTRAINT FK_COLLECTS_TASK FOREIGN KEY (CTask_Name) REFERENCES YDB_Task (Task_Name) )
And Django's 'inspectdb' command gave me this model :
class YdbCollects(models.Model): coriginal_data_type = models.ForeignKey('YdbOriginalDataType', db_column='COriginal_Data_Type_ID') # Field name made lowercase. ctask_name = models.ForeignKey('YdbTask', db_column='CTask_Name') # Field name made lowercase. class Meta: managed = False db_table = 'ydb_collects' unique_together = (('COriginal_Data_Type_ID', 'CTask_Name'),)
And when I run 'makemigrations' command, It gives me error message : 'unique-together refers to the non-existent field 'COriginal_Data_Type_ID' and 'CTask_Name'.
When I change
unique_together = (('COriginal_Data_Type_ID', 'CTask_Name'),)
Into
unique_together = (('coriginal_data_type ', 'ctask_name'),)
then It goes OK but is this correct way to go?
Seems like code below has different schema from my DDL...Original foreign key I defined was id of data type, not data type itself.
Did I do something wrong here? Why does unique_together() has column names? Every Django models generated with MySQL's PRIMARY_KEY(Key1, Key2, ...) gives me this error!