Opened 11 years ago
Last modified 11 years ago
#21637 closed Bug
Defining objects of models having custom field without any parameter. — at Version 2
Reported by: | ANUBHAV JOSHI | Owned by: | ANUBHAV JOSHI |
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Component: | Database layer (models, ORM) | Version: | 1.6 |
Severity: | Normal | Keywords: | |
Cc: | Triage Stage: | Unreviewed | |
Has patch: | no | Needs documentation: | no |
Needs tests: | no | Patch needs improvement: | no |
Easy pickings: | no | UI/UX: | no |
Description (last modified by )
When we define any model, then we can create its object as obj=ModelClassName(). But when we define custom fields we just cannot do the same always. If we are using to_python() method, then it shows up error.
If a define my model as:
from django.db import models class LField(models.Field): __metaclass__ = models.SubfieldBase def db_type(self, connection): return 'longtext' def to_python(self, value): return long(value) class Person(models.Model): name = models.CharField(max_length=80, blank=True, null=True) something_else = LField() class Person2(models.Model): name = models.CharField(max_length=80, blank=True, null=True) ph = models.CharField(max_length=80, blank=True, null=True)
Then it is not possible to define an object of Person type without giving parameters.
i.e.
p=Person() raises ValueError
p=Person2() works fine as it should like in case of any other class.
Change History (2)
comment:1 by , 11 years ago
Owner: | changed from | to
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Status: | new → assigned |
comment:2 by , 11 years ago
Description: | modified (diff) |
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