Opened 15 years ago
Last modified 13 years ago
#12197 closed
parse_accept_lang_header parse HTTP_ACCEPT_LANGUAGE with wrong Quality factors — at Version 2
Reported by: | Owned by: | nobody | |
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Component: | Internationalization | Version: | 1.1 |
Severity: | Keywords: | ||
Cc: | Triage Stage: | Unreviewed | |
Has patch: | no | Needs documentation: | no |
Needs tests: | no | Patch needs improvement: | no |
Easy pickings: | no | UI/UX: | no |
Description (last modified by )
According to the RFC 2616 <http://www.w3.org/Protocols/rfc2616/rfc2616-sec14.html>, HTTP_ACCEPT_LANGUAGE could have several languages options, such as
da, en-gb;q=0.8, en;q=0.7
So, django parse those string with parse_accept_lang_header method, and order the options base on its 'q' quality factor.
But the re.split seems return a list with a empty string as first element, such as
s = 'da, en-gb;q=0.8, en;q=0.7' r.split(s) ['', 'da', None, '', 'en-gb', '0.8', '', 'en', '0.7', '']
But parse_accept_lang_header use it from index 0, it means they align to wrong index
To fix the issues, you could modify the accept_language_re, or use the return list from index 1.
def parse_accept_lang_header(lang_string): """ Parses the lang_string, which is the body of an HTTP Accept-Language header, and returns a list of (lang, q-value), ordered by 'q' values. Any format errors in lang_string results in an empty list being returned. """ result = [] pieces = accept_language_re.split(lang_string) if pieces[-1]: return [] for i in range(0, len(pieces) - 1, 3): first, lang, priority = pieces[i : i + 3] if first: return [] priority = priority and float(priority) or 1.0 result.append((lang, priority)) result.sort(lambda x, y: -cmp(x[1], y[1])) return result
Change History (2)
comment:1 by , 15 years ago
comment:2 by , 15 years ago
Description: | modified (diff) |
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