linebreaksbr and linebreaks can not work in template filters

[何翔宇(Sean Ho)]

In template, linebreaksbr and linebreaks can convert newlines in a piece of plain text to HTML line breaks ( <br>).

They all use the same way which is "replace('\n', '<br>')", the correct way is “"replace(r'\n', '<br>')”.

@register.filter(is_safe=True, needs_autoescape=True)
@stringfilter
def linebreaksbr(value, autoescape=True):
    """
    Convert all newlines in a piece of plain text to HTML line breaks
    (``<br>``).
    """
    autoescape = autoescape and not isinstance(value, SafeData)
    value = normalize_newlines(value)
    if autoescape:
        value = escape(value)
    return mark_safe(value.replace('\n', '<br>'))

@keep_lazy_text
def linebreaks(value, autoescape=False):
    """Convert newlines into <p> and <br>s."""
    value = normalize_newlines(value)
    paras = re.split('\n{2,}', str(value))
    if autoescape:
        paras = ['<p>%s</p>' % escape(p).replace('\n', '<br>') for p in paras]
    else:
        paras = ['<p>%s</p>' % p.replace('\n', '<br>') for p in paras]
    return '\n\n'.join(paras)

Attachments is error result in html.

[Claude Paroz]

Like I said on the PR, presenting a failing test case is the key to convince us Django is at fault. Reopen the ticket as soon as you have it.