= CookBook - Template tag Regroup =

If you need to group a list of objects by a choice like fied '''choices = CATEGORY_CHOICES''',
here is the trick.

A Model.
{{{
#!python

CATEGORY_CHOICES = (
	(1, 'Entrées'),
	(2, 'Poissons et crustacés'),
	(3, 'Viandes et volailles'),
	(4, 'Légumes et accompagnements'),
	(5, 'Desserts'),
	(6, 'Boissons'),
	(8, 'Autres'),
)	

class Recette(meta.Model):
	[...]
        categorie = meta.SmallIntegerField(choices = CATEGORY_CHOICES)

}}}

The Rrgroup tag in action, the thing is that you don't want to display the category
number bit its corresponding name. (e.g not '1' but 'Entrées').

Temmplate
{{{
#!python

{% regroup recettes by categorie as grouped %}
<ul>
{% for group in grouped %}
	<li>{{ group.list.0.get_categorie_display }} 
    <ul>
        {% for item in group.list %}
        <li>{{ item }}</li>
        {% endfor %}
    </ul>
{% endfor %}
</ul>

}}}