id	summary	reporter	owner	description	type	status	component	version	severity	resolution	keywords	cc	stage	has_patch	needs_docs	needs_tests	needs_better_patch	easy	ui_ux
9315	Keyword arguments with spaces and the url tag	Alexis Bellido	Natalia Bidart	"Hi, I asked about this on the django-users group and was told it was probably a bug so I'm reporting it:

I was testing named url patterns and I have something like this in my URLConf:

{{{
url(r'^search/(?P<words>.*)$', 'books.views.search', name='search_page'),
}}}

The view is defined like this:

{{{
def search(request, words):
}}}

Now I'd like to print a link to the search page with certain words from a template and used the url tag like this:

{{{
<p>{% url search_page words=""someword"" %}</p>
}}}

When viewing on the browser I get something like '/search/someword', which is good. My question is how do I pass more than one word in the 'words'
parameter?

If I do this:

{{{
<p>{% url search_page words=""someword otherword"" %}</p>
}}}

I get this error:

{{{
TemplateSyntaxError at (my page name here)

Could not parse the remainder: '""someword' from '""someword
}}}

Can the url tag handle parameters with spaces?"		closed	Template system	1.0		fixed	url, tplrf-fixed, pycamp2009	Robert matiasb	Accepted	1	0	0	0	0	0