id	summary	reporter	owner	description	type	status	component	version	severity	resolution	keywords	cc	stage	has_patch	needs_docs	needs_tests	needs_better_patch	easy	ui_ux
9743	Problem in admin when displaying foreignkey of a model that reference himself	daniels	Jeremy Dunck	"{{{
class Client(models.Model):
  name = models.CharField()

class Module(models.Model):
  client = models.ForeignKey(Client)

class SuperModule(Module):
  sample = models.ForeignKey(Module)
}}}

If in the django.admin.contrib, we want to display SuperModule with a 
list_display = ('name', 'client')
it will not work unless we remove the foreign key to Module.
It was not tested with the simple code above, but in our complete code.

After some investigation, I found a way where an error occured when doing 'as_sql()' on a
query_set.  The error was about an extra parameter to avoid.update().  And some lines below, 
the same function call but with a small difference in parenthesis and works OK.
"		closed	Database layer (models, ORM)	1.0		worksforme		daniels@…	Accepted	1	0	1	0	0	0